Question
A 400 m long train crosses a platform twice its length
in 2 min. Find the speed of the train.Solution
Speed of train = (Length of train + Length of Platform)/Required time Length of train = 400 m Crossing time of platform = 2 Γ 60 = 120 sec Length of platform = 400 Γ 2 = 800 m Let the speed of train be x. Speed of train = (400 + 800)/120 β Β x = 1200/120 = 10 m/s
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