Question
Train P travelling at 55 km/hr crosses another train Q,
having three fourth of its length and travelling in opposite direction at 35 km/hr in 14 seconds. Train P passed a railway platform in 36 seconds. Find the length of platform.Solution
Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (55 + 35) x 5/18 = {x + (3x/4)}/14 ⇒ 90 x 5/18 = (7x/4)/14 ⇒ x = 200 m Therefore, let the length of the platform be y metre ⇒ 55 x 5/18 = (200 + y)/36 ⇒ 550 = 200 + y ⇒ y = 550 – 200 = 350 m
What is the simplified value of the given expression?
3(sin² 30° + sin² 60°) + 6sin 45° - (3sec 60° + cot 45°)
- Find the simplified value of the expression:sin 2 45 o Ā + sin 2 60 o Ā - (1/3) X tan 2 60 o
If θ is a positive acute angle and cos² θ + cosā“θ = 1, then the value of tan²θ + tanā“θ is?
Find the value of the given trigonometric expression:
(sin 15°cos 75° + cos²15°) à sin 30° + (cos 60°tan 45°) à sec 60°
...Find the maximum value of (20sin A + 15cos A).
Find the exact value of cos120°
- If sin(A + B) = ā3/2 and cos(A + 2B) = 1/2, where 0° < A, B < 90°, then find the value of tan(2A).
If cosec (2A + B) = 2 and cosec (A + B) = 1, find the value of (3A ā B).
A tower is 60 meters high. From a point on the ground, the angle of elevation of the top of the tower is 30°. Find the distance of the point from the b...
- Find the maximum value of (12sin A + 16cos A).