Let length of train A = x Length of platform = 2x Speed = distance/time ⇒ 162 x 5/18 = (x + 2x)/22 ⇒ x = 330 m = length of train A Length of platform = 330 x 2 = 660m For train B, Speed = distance/time ⇒ (660 + 760)/36 x (18/5) ⇒ 142 km/hr
Cognizance under section 498A of IPC can be taken:
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