Question
'Ravi' can complete some work alone in 25 days. 'Shyam'
is twice as efficient as 'Mohan' and four times as efficient as 'Ravi'. If 'Ravi' and 'Mohan' start working together, then after how many days should 'Shyam' replace them so that the work gets completed in exactly 10 days?Solution
ATQ, Let the total work be 100 units. Efficiency of 'Ravi' = 100 ÷ 25 = 4 units/day Efficiency of 'Shyam' = 4 X 4 = 16 units/day Efficiency of 'Mohan' = 16 ÷ 2 = 8 units/day Let the number of days for which 'Shyam' worked alone be 'd'. So, (d X 16) + (10 - d) X (4 + 8) = 100 Or, 16d + 120 - 12d = 100 Or, 'd' = 5 So, 'Shyam' worked alone for 5 days 'Shyam' should've joined them after (10 - 5) = 5 days
√323.89  × (3.20) ÷ 9.02 =?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
23.98% of 624.99 = 19.98% of ? + 14.98% of 639.99
Direction: Please solve the following expression and choose the closest option
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
12, 16, ?, 36, 52, 72Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(6859.01)1/3  × 10.11 × 14.47 ÷ 20.32 = ? + 45.022
33.33% of 809.891 + 66.66% of 212.91 = ?
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