Akshat and Saksham are assigned two work-sites at 28 km and 35 km from their house. They left together and reached exactly at 10:00
A.M. One day, the sites were swapped and Akshat started 9 minutes earlier than Saksham to reach on time. Find the speed of Akshat.

Solution

ATQ, Distance covered by Akshat and Saksham = 28 km and 35 km, respectively Since, both of them reached their respective places at same time Therefore, ratio of speeds of Akshat and Saksham = 28:35 = 4:5 Let the speeds of Akshat and Saksham be 4x km/hr and 5x km/hr, respectively Time taken by Akshat on the day of interchange = 35/(4x) hours Time taken by Saksham on the day of interchange = 28/(5x) hours According to the question, (35/(4x)) – (28/(5x)) = 9/60 Or, (35/4 − 28/5)/x = 3/20 Or, ((175 − 112)/20)/x = 3/20 Or, (63/20)/x = 3/20 Or, 63/(20x) = 3/20 Or, 63/x = 3 Or, x = 21 Therefore, speed of Akshat = 4x = 84 km/hr