Question
If Ramesh covers a certain distance at 12 km/h, he
arrives 5 hours later than the scheduled time. If he travels at 20 km/h, he reaches 2 hours earlier than the scheduled time. What is 50% of the distance travelled by Ramesh?Solution
ATQ:
Let the distance travelled by Ramesh = ‘d’ km
Let the usual time taken by Ramesh to travel this distance = ‘t’ hours We have,
d ÷ 12 = t + 5…………………..(i)
Also, d ÷ 20 = t – 2…………………(ii) Equation (i) – Equation (ii), we get
(d/12) – (d/20) = t + 5 – (t – 2) = 7
Or, (5d – 3d) ÷ 60 = 7
So, d = (60 × 7) ÷ 2 = 210 So, 50% of the distance travelled by Ramesh = 210 × 0.5 = 105 km
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.022% of 20) × 46 ÷ 2.03 – 8.78 × 5.72 + 50.23% of 4820 = ?
21.11 × 4.98 + 22.03 × 4.12 – 31.95 + 95.9 × 3.02 =?
90.004% of 9500 + 362 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
63.981 + 64.001 + 65.08019 + 63.11112 =?
630 × 256 ÷ 30 ÷ 56 = ? x 4
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(24.98)2 = ?2Â + (14.99)2
- 349.99% of 11.98 = ?– 12.5% of 143.99
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