Question
If Ramesh covers a certain distance at 12 km/h, he
arrives 5 hours later than the scheduled time. If he travels at 20 km/h, he reaches 2 hours earlier than the scheduled time. What is 50% of the distance travelled by Ramesh?Solution
ATQ:
Let the distance travelled by Ramesh = ‘d’ km
Let the usual time taken by Ramesh to travel this distance = ‘t’ hours We have,
d ÷ 12 = t + 5…………………..(i)
Also, d ÷ 20 = t – 2…………………(ii) Equation (i) – Equation (ii), we get
(d/12) – (d/20) = t + 5 – (t – 2) = 7
Or, (5d – 3d) ÷ 60 = 7
So, d = (60 × 7) ÷ 2 = 210 So, 50% of the distance travelled by Ramesh = 210 × 0.5 = 105 km
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