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ATQ,
Let the time taken by 'P' to finish = t seconds
Then, distance covered by 'R' in t seconds = 300 - 45 = 255 metres
So, ratio of speeds of 'P' and 'R' = 300 : 255 = 20 : 17
Now, R beats Q by 30 metres, so:
Ratio of speeds of 'R' and 'Q' = 300 : (300 - 30) = 300 : 270 = 10 : 9
Now, combine:
Ratio of speeds of P, R, Q = 20×10 : 17×10 : 17×9 = 200 : 170 : 153
So, when 'P' runs 300 metres, 'Q' runs = 300 × (153/200) = 229.5 metres
Therefore, 'P' beats 'Q' by 300 - 229.5 = 70.5 metres
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