Question
In a 1.6 km race, 'A' gives 'B' a head start of 300
meters, but still 'A' wins the race by 100 meters. If 'B' takes 15 minutes to complete the race, calculate the time taken by 'A' to finish the race.Solution
Distance covered by 'B' when 'A' covers 1600 metres = 1600 - 300 - 100 = 1200 metres Ratio of speed of 'A' and 'B' respectively = 1600:1200 = 4:3 So, ratio of time taken by 'A' and 'B' to complete the race respectively = 3:4 Therefore, required time = (15/4) X 3 = 11.25 minutes
? = 41.92% of 49.96% of (45.07 1.97 – 4.98 2.03 )
(80.95) (1/4) + (3.05) 3 - 119.78 × 2.15 + (14.98)2 = ?
? + 154.99 – 110.01 = 30.01 × 4.98
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(278% of 695) ÷ 543 =?
{26.11 x 13.96 - (346.95 - 26.04 x 4.18)} = ?
[15.87% of 599.97 + 40.08 × ?] ÷ 4.04 = 8.082.02
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
185.92 ÷ 5.98 - (4.002)2 + 114.03 of 5.03 ÷ 18.99 of 6.04 = 5.01 of 2.99 + ? ÷ 12.02
`(13.022)^(2)+ (42.93)^(2)-(53.125)^(2)+(192.33xx14.88)=?- (88.44)^(2)- (42.03 xx 23.12)`
