Question
Train A whose length is 180m is crosses a man standing
in the bridge in 4.5 seconds. Train B whose length is165 m, is running at a speed of 63 km/hr and moving in opposite direction to that of train A. Find the time required for train A to cross train B?Solution
According to the question, 180 = 4.5 * speed of train A Speed of train A = 40 m/s Speed of train B = 63*(5/18) = 35/2 m/s 345 = (40 + 35/2)* T (345*2)/ 115 = T T = 6 seconds
13 14 22.5 ? 120 363
...70    191    47    216    ?    245
65    69   77 93  ?    189
49Â Â Â Â Â 121Â Â Â Â Â Â Â 169Â Â Â Â Â Â 289Â Â Â Â Â Â 361Â Â Â Â Â Â ?
...14 15 34 116 460 2325
...If 6 4 x 5.75 9,
Then, (x²-1) = ?
...97 106 121 138 157 180
...20    60      180      540     ?     4860
...12    16    43    ?       184    220
...If 152,   242,    x ,  332,   404,    314,
then find the value of (2x – 1)?
...