Speed of the train = 72 kmph i.e., 72 × 5/18 = 20m/s So, total distance cover in 20 seconds = 20 × 20 = 400m Speed of Car = 36kmph i.e, 36 × 5/18 = 10m/s Relative speed of Car and Train in Opposite direction = 20 + 10 = 30 m/s So, Distance cover in 6.5 seconds = Length of the train = 30 × 6.5 = 195m Hence, Length of the Platform = 400 – 195 = 205m
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Find the smallest number which when successively divided by 4, 7 and 5 will give the remainder 2, 1, 3.
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(141.95 – 112.06) × (45.21 – 38.99) = ?
