Question
1000 metres long train crosses a man who is moving in
the same direction with a certain speed, in 40 seconds. If the same train can cross a tree in 20 seconds with the same speed, then find the speed of the man.Solution
Speed of train = 1000/20 = 50 m/sec Let the speed of the man be βsβ m/sec Relative speed of the train = (50 β s) m/sec According to the question, (50 β s) = 1000/40 Or, s = 50 β 25 = 25 Therefore, speed of the man = 80 m/sec
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