Question
1000 metres long train crosses a man who is moving in
the same direction with a certain speed, in 40 seconds. If the same train can cross a tree in 20 seconds with the same speed, then find the speed of the man.Solution
Speed of train = 1000/20 = 50 m/sec Let the speed of the man be βsβ m/sec Relative speed of the train = (50 β s) m/sec According to the question, (50 β s) = 1000/40 Or, s = 50 β 25 = 25 Therefore, speed of the man = 80 m/sec
242 + 80% of 1620 = ? Γ 16 β 35% of 800
(γ(0.5)γ^(1/3)Β Γ γ(1/125)γ^(1/4)Β Γ γ25γ^(1/6)Β Γγ(6.25)γ^(2/3))/(γ(2.5)γ^(2/3)Β Γ 5^(-1/2)Β Γ γ(1/5)γ^(-2)Γγ3125οΏ½...
What will come in the place of question mark (?) in the given expression?
35 X 72 + 35 X 28 = ? X β16Β
17.6% of 250 + β? = 70% of 90
√144 × √121 + 25% of 600 = ? + 256
(6630 Γ· 13 + 6120 Γ· 12) Γ· (17 Γ 3) = ?Β
40 Γ 5 + 27) Γ 9 = ?
- Evaluate: 168 Γ· 12 Γ 5 + 190 β 20% of 450
What will come in the place of question mark (?) in the given expression?
{180 + (2250/15)} Γ· 11 = ?2 + 14
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