1000 metres long train crosses a man who is moving in the same direction with a certain speed, in 40 seconds. If the same train can cross a tree in 20 seconds with the same speed, then find the speed of the man.

Speed of train = 1000/20 = 50 m/sec Let the speed of the man be ‘s’ m/sec Relative speed of the train = (50 – s) m/sec According to the question, (50 – s) = 1000/40 Or, s = 50 – 25 = 25 Therefore, speed of the man = 80 m/sec

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^{2}+ y^{2}= 41 where x, y ≥ 0, then the value of x + y will be:If the sides of a triangle measure 21 cm, 35 cm and 28 cm, what is the measure of its in radius? (in cm)

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