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Let the speed of B be x kmph ⇒ Time taken by B to cover 40 km = 40/x ⇒ Time taken by A = (40/x) + 2 So, the speed of A = (20x)/(20 + x) ----(1) Distance = 80 km ⇒ Time taken by B to cover 80 km = 80/x ----(2) ⇒ Speed of A when he doubles his speed = (40x)/(20 + x) ⇒ Time taken by A to cover 80 km = (40 + 2x)/(x) ----(3) A.T.Q., From (2) and (3) (80/x) + (3/2) = (40 + 2x)/x ⇒ (40 + 2x)/2x - 80/x = 3/2 ⇒ 2 (40 + 2x - 80) = 3x ⇒ 2 (2x - 40) = 3x ⇒ 4x - 80 = 3x ⇒ 4x - 3x = 80 ⇒ x = 80 ⇒ Speed of B = 80 kmph Distance = 90 km Time taken by B = 90/80 = 1(1/8) hrs
A train passes an electrical pole in 15 seconds and passes a platform 345 m long in 60 seconds. Find the length of the train.
A train 600 metres long is running at a speed of 54 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:
A train 480 metre long takes 36 sec to cross a man running at a speed of 7 km/hr in the direction same to that of train. What is the speed of the train?
