Question
A train covers a distance of 60 km at the speed of 30
km/h the next 130 km distance covers with a speed of 50 km/h and last 56 km with the speed of 40 km/h find the average speed of the train?Solution
Since the train covers different distance with different speeds. So, Average speed = Total Distance/Total Time Total distance = 60 + 130 + 56 = 246 km Time1 = 60/30, Time2 = 130/50 & Time3 = 56/40 Total Time = 60/30 + 130/50 + 56/40 Therefore, Average Speed = 246/(60/30 + 130/50 + 56/40) = 41 km/hr
A $ B means A X B, A & B means A - B, A % B means A ÷ B and A # B means A + B, then what is the value of 320 & 80 # 120 % 24 $ 50?
Statements:
V ≤ P < S = B; T < U ≤ I = B; N < J < T
Conclusions:
I. J > P
II. N < S
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What is the code for ‘it’?
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