Question
Simplify: 3β50 β 2β8 + β18
Solution
ATQ, β50 = 5β2, β8 = 2β2, β18 = 3β2 = 3(5β2) β 2(2β2) + 3β2 = 15β2 β 4β2 + 3β2 = 14β2
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