Question
Simplify: 3β50 β 2β8 + β18
Solution
ATQ, β50 = 5β2, β8 = 2β2, β18 = 3β2 = 3(5β2) β 2(2β2) + 3β2 = 15β2 β 4β2 + 3β2 = 14β2
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0
I. 2x² - 11x + 12 = 0
II. 12y² + 29y + 15 = 0
I. 40xΒ² + 81x + 35 = 0
II. 63yΒ² + 103y + 42 = 0
I. 3p² - 11p + 10 = 0
II. 2q² + 13q + 21 = 0
I. 2x2 β 19x + 45 = 0
II. y2 β 14y + 48 = 0
If the roots of the quadratic equation 6mΒ² + 7m + 8 = 0 are Ξ± and Ξ², then what is the value of [(1/Ξ±) + (1/Ξ²)]?
Β If x satisfies xΒ² β 14x + 40 = 0, find x.
I. 81x - 117βx + 40 = 0
II. 81y - 225βy + 136 = 0
If the roots of the quadratic equation 5xΒ² + 4x + 6 = 0 are Ξ± and Ξ², then what is the value of [(1/Ξ±) + (1/Ξ²)]?
...I. 4xΒ² - 21 x + 20 = 0
II. 8yΒ² - 22 y + 15 = 0