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    Question

    ((0.1)3+ (1.8)3+ (1.1)3

    - 0.3 ×1.8 ×1.1)/((0.1)2+ (1.8)2+ (1.1)2- (0.18)- (0.11)- (1.8 ×1.1))= ? What value should come in place of the question-mark (?) in the following questions:
    A 3 Correct Answer Incorrect Answer
    B 6 Correct Answer Incorrect Answer
    C -3 Correct Answer Incorrect Answer
    D -5 Correct Answer Incorrect Answer
    E 5 Correct Answer Incorrect Answer

    Solution

    a³ + b³ + c³ - 3abc = (a+b+c) (a² + b² + c² -ab –bc -ca) According to the question, (уАЦ(0.1)уАЧ^3+ уАЦ(1.8)уАЧ^3+ уАЦ(1.1)уАЧ^3- 0.3 ×1.8 ×1.1)/(уАЦ(0.1)уАЧ^2+ уАЦ(1.8)уАЧ^2+ уАЦ(1.1)уАЧ^2- (0.18)- (0.11)- (1.8 ×1.1)) ⇒ ((0.1+1.8+1.1) ((0.1)^2+ (1.8)^2+ (1.1)^2- (0.18)- (0.11)- (1.8 ×1.1)))/(уАЦ(0.1)уАЧ^2+ уАЦ(1.8)уАЧ^2+ уАЦ(1.1)уАЧ^2- (0.18)- (0.11)- (1.8 ×1.1)) ⇒ (0.1+1.8+1.1) = 3

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