Question
The amount in a bank account after 3 years is ₹1350
when the interest is compounded annually at a rate of 10%. What was the principal amount?Solution
Let the principal amount be P. The formula for compound interest is: Amount = P(1 + r/100)ᵗ , where r = 10%, t = 3 years, and the amount is ₹1350. Substitute into the formula: 1350 = P(1 + 10/100)³ 1350 = P(1.1)³ 1350 = P × 1.331 Now, solve for P: P = 1350 / 1.331 = ₹1014.3 (approximately ₹1014) Therefore, the principal amount is ₹1014. Correct option: a
Statement: M>T≤Z; T>Q ; X ≥R>Q
I. X ≥ M
II. Q < M
Statements: P * R, M & N, R $ M
Conclusions: a) P @ M b) P $ M
...In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and the...
Statement: B > C = J; B > S > E; B < N
Conclusion: I. E < C II. J ≤ E
Statements: X @ Y % M % N; M $ P $ Z
Conclusions : I. Y % Z II. X @ N �...
Statements: V ≤ R ≥ Q; R ≤ N < Y; I > Y ≤ S
Conclusions:
I. V ≤ S
II. I > Q
III. S > N
Statements: R % B, B & T, T @ E, E % G
Conclusions : I. T $ R II. R @ E III. B @ G
...Statement: H > G = M > S ; G `>=` T > L; M `<=` F < U
Conclusion: I. L > M II. G < U
...How many such pairs of letter are there in the word TELEPHONE, each of which has as many letters between them in the word as in the English alphabet?
Statements: B > C; D > E = F < G ≥ H; C > I = D
Conclusions:
I. B < E
II. G > E
III. I < B
