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ATQ,
Let sum invested = Rs. ‘P’ ATQ, P × {1 + (r/100)}2 – P = {P × (2r + 1) × 2}/(2 × 100) Or, 1 + (r2 /1002 ) + (r/50) – 1 = (r/50) + (1/100) Or, (r2 /1002 ) + (r/50) = (r/50) + (1/100) Or, (r2 /1002 ) = (1/100) Or, r2 = 100 So, r = 10 {Since, rate cannot be negative so we can drop 'r' = -10} So, the value of ‘r’ = 10
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