When the interest accrued on a certain principal amount over four years is 4/9 times the interest earned on the same principal amount after another four years, and the annual interest rate is denoted as r%, what is the value of 'r'?
ATQ, Let the amount be Rs. ‘100X’. So, [100X × 4 × r/100 ]= [(4/9) × (100X + 100X × 4 × r/100) Or, 4Xr = (4/9) × (100X + 4Xr) Or, 4r = (4/9) × (100 + 4r) Or, 36r = 400 + 16r Or, 20r = 400 Or, r = 20
1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 × 9.05 = ?
5555.05 + 500.05 + 5000.005 + 5.005 =?
(462.23 × 127.84 ÷ 153.88) ÷ √(31.98 × 7.92) = ? ÷ 15.15
(29.97%) of 9840 + ? + (45.17% of 1240) = (31.955% of 11750)
24.11 × 5.98 + 25.03 × 3.12 – 34.99 + 96.9 × 5.02 =?
6401.23 × `1 3/4` - 352.87 × ? = 10443.789
(√4623.9 + √484.2) – √2303.97 ÷ √1296.4 × √35.98 ÷ √15.99 = ?
√? + √626 × 13.998 - 6.02 × 2.97 = 345.995
(67.2)2 – (8.9)2 – (22.02)2 =?
(15.022% of 20) × 46 ÷ 2.03 – 8.78 × 5.72 + 50.23% of 4820 = ?
