Question
Rs. (X+500) is invested in scheme A for 5 years at 10 %
simple interest. The received amount is then invested in another scheme B offering 10% interest for 2 years at compound interest. Interest received from scheme B was Rs.3780. Find the value of X.Solution
SI = (X + 500) × 50/100 =  (X + 500)/2 Amount = (x + 500) + {(X + 500)/2} = 3/2 × (X + 500) CI = 3780 So, 3/2 × (X + 500) × 21/100 = 3780 X + 500 = (3780 × 100 × 2)/(21 × 3) = 12000 X = 12000 – 500 = Rs. 11500
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
17% of 250 + ? = 108
32 + 26 × (484 ÷ 44) + 450 ÷ 9 = ?Â
40 × 5 + 27) × 9 = ?
What will come in the place of question mark (?) in the given expression?
193...
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
What will come in the place of question mark (?) in the given expression?
√1296 + (2/3 of 45% of 480) = ?
- Determine the value of ‘p’ if p = √529 + √1444
120% of 250 + 110 + 135 ÷ 5 = ?