Question
A man invested certain sum at simple interest of r% p.a.
such that it amounts to 130% of itself in 3 years. Find the interest earned when Rs. 3000 is invested at simple interest of r% p.a. for 3 years.Solution
Let the sum invested be Rs. ‘P’ Therefore, interest earned in 3 years = 1.3P – P = Rs. 0.3P ATQ; 0.3P = (P × r × 3) ÷ 100 Or, r = 30 ÷ 3 Or, r = 10 So, required interest earned = (3000 × 10 × 3) ÷ 100 = Rs. 900
More Simple and compound interest Questions
7, 8, 12, 21, 37, ?
- What will come in the place of question mark (?) in the given expression?
35% of 400 - 20% of 300 = (? - 30) X 2 Evaluate: 18 ÷ 3 × 4 + 6 − 5
What will come in the place of question mark (?) in the given expression?
96 ÷ (9 - 6.6) + 17.5 X 6 = ? ÷ 8
242 + 80% of 1620 = ? × 16 – 35% of 800
(-251 × 21 × -12) ÷ ? = 158.13
- What will be come in place of (?) in the given expressions.
(58% of 250) + (42% of 150) = ? What value should come in place of the question mark (?) in the following question?
2000 ÷ 10 + 250 × 2 �...
What will come in place of the question mark (?) in the following questions?
55 ÷ 11 × 6 + ?2 = 47 × 2
