Question
A man invested certain sum at simple interest of r% p.a.
such that it amounts to 130% of itself in 3 years. Find the interest earned when Rs. 3000 is invested at simple interest of r% p.a. for 3 years.Solution
Let the sum invested be Rs. ‘P’ Therefore, interest earned in 3 years = 1.3P – P = Rs. 0.3P ATQ; 0.3P = (P × r × 3) ÷ 100 Or, r = 30 ÷ 3 Or, r = 10 So, required interest earned = (3000 × 10 × 3) ÷ 100 = Rs. 900
More Simple and compound interest Questions
What will come in the place of question mark (?) in the given expression?
133 ÷ 19 X √576 + ? ÷ 2 = 32 X 7.5What will come in the place of question mark (?) in the given expression?
(96 - 59) X 6 + ?2 = 136.5 X 4
- What will come in the place of question mark (?) in the given expression?
40% of (320 ÷ 4) + 2² X 25 = ? + 42 1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)     Â
(1748 ÷ 8) + 76.8 × 35 =(? × 4) + (42 × 35.5)
- What will come in place of the question mark (?) in the following questions?
0.5×120+25=? √14400 x √8100 - (60)² = ? + (80)²
What will come in place of the question mark (?) in the following expression?
?% of 600 + 15 × 28 = 30% of 1800
- What will come in place of (?), in the given expression.
(4² + 6²) × 2 = ? 300% of (3341 – 471) = ? × (√4225/195)
