Question
Suresh earned an interest of Rs. 1161 on principal
amount of Rs. 3600 at some rate of compound interest in 2 years. How much more/less interest would he have earned on Rs. 4000 at the same rate of simple interest for the same duration?Solution
Let, rate of interest be ‘r’% per annum So, 1161 = 3600 × {(1 + r/100)2 – 1} 129/400 = {(1 + r/100)2 – 1} 529/400 = (1 + r/100)2 (23/20)2 = (1 + r/100)2 23/20 = 1 + r/100 3/20 = r/100, r = 15 So, simple interest earned = 4000 × 0.15 × 2 = Rs. 1200 Required amount = 1200 – 1161 = Rs. 39
24.035 × √? = 4607.89 ÷ 11.8259Â
What approximate value will replace the question mark (?) in the following?
18.99...
‘A’ and ‘B’ can build a wall in 8 days and 12 days, respectively. If ‘A’ started building the wall alone but after 4 days he was replaced by...
14.99% of 7820 + 5535.25 ÷ 123.001 - ? = 84
[(2/3 of 899.79) + 25% of 500.21] × (√195.77 + 30.03% of 399.79) = ?
`root(3)(725.87)` `-:` `sqrt(81.033)` Â + 49.88% of 809.77 = ? - (14.78Â `xx` Â 52.2)
(?)2 + 3.113 = 22.92 – 61.03Â
(48.89 ÷ 7.08) × (35.96 ÷ 4.11) + (9.02 × 1.99) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
30.02% of 420.11 + 44.96% of 499.96 - 203.12 = ?