Question
A man wants to invest Rs 20,220 in bank account of his
two sons whose age were 12 years and 16 years in such a way that they will get equal amount at age of 120 years @ 33(1/3)% per annum compounded annually. Find the share of younger son?Solution
For younger son Let the principal be x Time = 120 – 12 = 108 years Rate = 100/3 % For elder son Let the principal be Rs (20220 – x) Time = 120 – 16 = 104 years Rate = 100/3 % Amount of younger = Amount of elder x (1 + r/100)108 = (20220 – x) (1 + r/100)104 x (1 + 100/300)108 = (20220 – x) (1 + 100/300)104 [x/(20220 – x)] = (4/3)104/(4/3)108 [x/(20220 – x)] = 1/(4/3)4 [x/(20220 – x)] = 81/256 337x = 1637820 x = 4860 Alternate method: y/x =(4/3)(difference) =(4/3)4 = 256/81 81/337 × 20,220 = 4860
120, 130, 145, 165, ?, 220
48, 24.5, ?, 39.75, 81.5, 206.25, 621.75
What will come in place of (?) Question mark in the given number series.
10, 15, 30, 75, 225, 787.5, ?
? , 864, 432, 144, 36, 7.2
97, 106, ?, 195, 411, 460
144, 288, 96, 384, 76.8, ?
23 40 67 104 ? 208
...16, 24, 36, ?, 81, 121.5
10296/72 + 3040 = (? × 4) + 1395
What will come in place of the question mark (?) in the following series?
68, 76, 61, 85, ?, 98
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