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CI = P [(1 + (R/100)n) – 1] => CI = x [(1 + (20/100)2) – 1] => CI = x [(36/25) – 1] => CI = 11x/25 Now, interest received was reinvested in scheme B. SI = (11x × 15 × 2)/(25 × 100) => SI = 33x/250 Amount = P + SI => 1430 = 11x/25 + 33x/250 => x = Rs.2500 Alternate Method: => (130/100) × 0.44x = 1430 => x = Rs.2500
540.11 ÷ 17.98 × 5.14 – 131.9 = √?
956.41 of 45.06% = ?
3.55% of 8120 – 66.66% of 540 = ? – 28% of 5500
59.978% of 800.315 - 229.95 = ? - 24.95% of 200.15
(1709.87 ÷ 38.09) + (768.11 ÷ 23.87) + (6599.81 ÷ 88.06) = ?
11.89 × 2.10 × 4.98 × 4.03 ÷ 7.98 of 15.03 = ?
(48.89 ÷ 7.08) × (35.96 ÷ 4.11) + (9.02 × 1.99) = ?
8 × 1099.95 ÷ 20.03 + 187.95 = ? × 3.96
Ankush and Binny began a business where Ankush contributed 75% of the total capital. Four months later, Chintu joined the busines...