Question
Rohit invested a certain amount at the rate of 6
p.c.p.a. and obtained a simple interest of Rs 8,730 at the end of 3 years. What amount of compound interest would he obtain on the same amount at the same rate of interest at the end of 2 years?Solution
Let the principal be Rs. x S.I = (P × R × T)/100 8730 = (x × 6 × 3)/100 x = 48500 Now, C.I. = P(1+ R/100)t – P C.I. = 48500 (1 + 6/100)2 – 48500 C.I. = Rs. 5994.60
Statements : R < O ≤ P < Q; M < L ≤ N > O; S < Q ≤ K
Conclusions:
I. M < K
II. N > R
III. O < S
A statement is given, followed by four conclusions given in the options. Find out which conclusion is true based on the given statement.
Statemen...
Statements: J = N, K < L, M ≥ J, N ≤ K
Conclusion:
I. N ≤ M
II. L > N
Statements:  T < U = S ≤  O, C > Y ≥ X, T > K = XÂ
Conclusions
I. O > K
II. C < T
III. U > K
ÂStatements: G > L = V ≥ Z ≤ O = Q < K < N
Conclusions:
I. L ≥ Q
II. Z < NStatements : T % W % B $ I @ LÂ
Conclusions :Â
I. B * TÂ
II. L © BÂ
III. L * T
In the following question the relationship between different elements is given in the statements followed by three conclusions I, II and III. Read the ...
Statement:
R ≤ P >K ≤ L; W ≤ X = K > O; Q > L
Conclusion:
I) W < L
II) L = W
Statement: M < N; L ≥ U; L ≥ Q; U > N ≥ T
Conclusion:
I. N > Q
II. Q > T
Statements : Q = R; S ≥ T; P ≤ Q; R > V; R > S; T ≥ U
Conclusions :
(i) R > U (ii) V ≥ U (iii) P = R (iv) P < R
Relevant for Exams:
