Question
Rohit invested a certain amount at the rate of 6
p.c.p.a. and obtained a simple interest of Rs 8,730 at the end of 3 years. What amount of compound interest would he obtain on the same amount at the same rate of interest at the end of 2 years?Solution
Let the principal be Rs. x S.I = (P × R × T)/100 8730 = (x × 6 × 3)/100 x = 48500 Now, C.I. = P(1+ R/100)t – P C.I. = 48500 (1 + 6/100)2 – 48500 C.I. = Rs. 5994.60
More Simple and compound interest Questions
- Find the value of the expression:
15 + 10 – 6 × [20 + 8 – 2 × (50 – 35)] (64 × 16) ÷ (4 × 16) 3 × 256 2 = 4 ?
[564 + 32 of 18 × 9 ÷ 12 + 162 ] ÷ 4 = ?
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
- 40% of 225 – 25% of 120 = 15% of ?
181/8 + 51/4 – 63/8 = ? + 9/2
(3500 ÷ √1225) × √(20.25) = ? ÷ 4
(11/12) × (18/22) × (4/3) + 3 = ?2
What will come in the place of question mark (?) in the given expression?
(5/8) × 1600 + (2400 ÷ 25) = ?
- What will come in place of (?) in the given expression.
(14)² – (12)² = ?