Question
The question below is based on the given series I. The
series I satisfy a certain pattern, follow the same pattern in series II and answer the questions given below. I: 70, 130, 270, 530, 1070, 2130 II: 300 ….. 2370. If 2370 is the (n – 1)th term, find the nth term?Solution
Explanation Answer: A Series I pattern: 70 * 2 - 10 = 130 130 * 2 + 10 = 270 270 * 2 – 10 = 530 530 * 2 + 10 = 1070 1070 * 2 – 10 = 2130 Series II pattern: 300 is the first term. 300 * 2 – 10 = 590 590 * 2 + 10 = 1190 1190 * 2 – 10 = 2370 (4th term) 2370 * 2 + 10 = 4750 (5th term)
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Disproportionate
