Question
The question below is based on the given series I. The
series I satisfy a certain pattern, follow the same pattern in series II and answer the questions given below. I: 180, 358, 712, 1416, 2816, 5600 II: 124 …… 1920. If 1920 is the nth term, find the value of (n+2).Solution
Series I pattern: 180 * 2 – 2 = 358 358 * 2 – 22 = 712 712 * 2 – 23 = 1416 1416 * 2 – 24 = 2816 2816 * 2 – 25 = 5600 Series II pattern: 124 is the first term 124 * 2 – 2 = 246 246 * 2 – 22 = 488 488 * 2 – 23 = 968 968 * 2 – 24 = 1920 (5th term)
More Series Questions
12.5% of (100 + ?) = 40
2/9 of 5/8 of 3/25 of ? = 40
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
7(1/2) – 3(5/6) = ? − 2(7/12)
280 ÷ 14 + 11 × 12 – 15 × 6 = ?
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
25% of 1000 + 10% of 150 – 22 × ? = 45
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
What will come in the place of question mark (?) in the given expression?
(40% of ? × 43 ) – 232 = 751
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
