Question
Two taps, A and B, can fill a cistern with a capacity of
576 liters in 36 minutes. If their filling efficiencies are in the ratio 5:3, determine how many minutes B alone would take to fill the cistern.Solution
Let the efficiencies of taps A and B be x and y respectively Then volume of tank/total efficiency = total taken time 576/ (x + y) = 36 (x + y) = 576/36 = 16 And their efficiencies are in the ratio 5:3 5a+3a = 16 a = 2 efficiency of A = 2Ă—5 = 10 efficiency of B = 2Ă—3 = 6 time taken by tap B = volume of tank/efficiency of tap B = 576/6 = 96 minutes
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