Question
A, B and C has total 60 toffies
with them. A has 25 toffies and the number of toffies with C is 5 less than that with B. How many toffies should be added with C, so that the ratio of toffies with A, B and C become 5:4:6?Solution
ATQ,
Given: Total toffees = 60, A has 25 toffees, C has 5 less than B. Let B have x toffees, So C has x − 5. Equation = 25+x+(x − 5) = 60. Solving gives x = 20. B = 20 toffees, C = 15 toffees. To make the ratio 5:4:6, let y be the toffees added to C. Equation = [(15+y)/6] = 5, solving gives y = 15.
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