Question
A man is supposed to distribute Rs. 7500 among his three
sons, A, B, and C in the ratio of 4:5:6, respectively, but mistakenly he distributed in the ratio of 5:4:6, respectively. Find the difference between amount received by A mistakenly and the amount that A should have actually receivedSolution
Amount that should be received by A initially = [4/(4 + 5 + 6)] × 7500 = Rs. 2000 Amount received by A mistakenly = [5/(5 + 4 + 6)] × 7500 = Rs. 2500 Therefore, required difference = 2500 – 2000 = Rs. 500
More Ratio Questions
12.5% of (100 + ?) = 40
2/9 of 5/8 of 3/25 of ? = 40
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
7(1/2) – 3(5/6) = ? − 2(7/12)
280 ÷ 14 + 11 × 12 – 15 × 6 = ?
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
25% of 1000 + 10% of 150 – 22 × ? = 45
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
What will come in the place of question mark (?) in the given expression?
(40% of ? × 43 ) – 232 = 751
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
