Question
A man is supposed to distribute Rs. 5000 among his three
sons, A, B, and C in the ratio of 3:2:5, respectively, but mistakenly he distributed in the ratio of 5:3:2, respectively. Find the difference between amount received by A mistakenly and the amount that A should have actually receivedSolution
Amount that should be received by A initially = [3/(3 + 2 + 5)] × 5000 = Rs. 1500 Amount received by A mistakenly = [5/(5 + 3 + 2)] × 5000 = Rs. 2500 Therefore, required difference = 2500 – 1500 = Rs. 1000
41.66% of 888 + 66.66% of 1176 = ?2 - 4√ 16 Â
Evaluate: 320 − {18 + 4 × (21 − 9)}
Simplify: 72 ÷ 6 × 3 − 8 + 4
118 × 6 + 13 + 83 = ?
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
(75 + 0.25 × 10) × 4 = ?2 - 14
26% of 650 + 15% of 660 – 26% of 450 = ?
115% of 40 + 3 × 4 = ? × 11 – 8