Start learning 50% faster. Sign in now
Here ABCD is a square and PQRSTU is Hexagon Let o is the center of circle then diagonal of square ABCD will 2r then area of square will be ½ (d)2 => ½ (2r)2 => 2r2 Now we have to find the area of hexagon we know that O angle is 60° then and ∠ S = ∠ T, then ∆ OST will be equilateral ∆, having side r. ∆OST = √3/4 × r2 In the Hexagon there will be 6 triangle and all are same then area of Hexagon will be => 6 × √3/4 × r2 (3√3/2) × r2 Ratio => Square : Hexagon => (2r/2) : (3√3/2) × r2 => 4 : 3√3
Select the option that represents the correct order of the given words as they would appear in an English dictionary.
1. Machine
44 : 4 :: 287 : 7 :: ? : 10
Select the correct combination of mathematical signs to sequentially replace the * signs and balance the given equation.
21 * 3 * 36 * 2 * 23 = 68
Select the option that will fill in the blank and complete the given series correctly.
100, 105, 111, 118, 126, 135, ______
Select the figure that will come next in the following figure series.
Select the fourth, seventh, eleventh and thirteenth letters of the word 'CATEGORISATION to form meaningful word(s).
Which of the following interchanges of signs would make the given equation correct?
110 ÷ 20 + 5 × 13 – 9 = 153