Question
A quantity h is directly proportional to t. When h =
84, then t = 28. When t = 40, then find the value of h.Solution
h ∝ t, which means, when 'h' increases then 't' will also increase and when 'h' decreases then 't' will also decrease. So, Let, h = k X t (where, 'k' is a proportionality constant) ATQ,
84 = k X 28 So, k = (84/28) = 3 When 't' = 40, then,
h = 3 X 40 = 120
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