Question
An integer 'p' is added to each of 6, 14, 22 and 34 so
that the resulting numbers will be in proportion in given order only. Find the value of '(p + 4)'.Solution
Let 'p' be the number that must be added to each of the given numbers so that they become proportional. i.e. (6 + p) :(14 + p) ::(22 + p) :(34 + p) So, (6 + p) ÷ (14 + p) = (22 + p) ÷ (34 + p) Or, (6 + p) (34 + p) = (22 + p) (14 + p) Or, 204 + 6p + 34p + p2 = 308 + 22p + 14p + p2 Or, 204 + 40p = 308 + 36p Or, 4p = 104 Or, 'p' = 26 Required value = p + 4 = 26 + 4 = 30
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