Total population of city P and Q is 3740 and 4320 respectively. If the ratio of number of males to females in city is P and Q is 6:5 and 5:4 respectively, then find the difference between number of males in city P and number of females in city Q.
Number of males in city P = 6/11 x 3740 = 2040 & number of females in city Q = 4/9 x 4320 = 1920 Desired difference = 2040 – 1920 = 120
Simplify-
x + 3(y + x – 2) – (x + y).
?% of (√196) × 24 + 344 = 428
(1748 ÷ 8) + 76.8 × 35 =(? × 4) + (42 × 35.5)
7/3 of 4/5 of 15/56 of ? = 83
12 × 6 + 24 – 36 of 5 + 160 = ?
779 + 136 – 334 = 270 + 121 + ?
54 ×70 ×33 ×42 =?
2/5 of 3/4 of 7/9 of 7200 = ?
78.89 × 81.03 – (16.83)² + 8.33% of 9602.87 = ? – 50.23
3/7 of 686 + 133(1/3)% of 33 – 69 =?
