Question
In the question, two quantities I and II are given. You
have to solve both the quantities to establish the correct relation between Quantity-I and Quantity-II and choose the correct option. Quantity I: A 200 litres chemical mixture contains 25% acid and the rest is water. How much water should be added so that the final acid to water ratio becomes 1:3? Quantity II: In a container, the ratio of honey to water is 7:2. If 21 litres of honey and 24 litres of water are added, the ratio becomes 2:1. Find the initial difference in litres between honey and water.Solution
ATQ,
Quantity I:
Acid = 25% of 200 = 50 litres
Water = 75% of 200 = 150 litres
Let added water = x litres 
50×3=1×(150+x)
150=150+x
X = 0
Water to be added = 0 litres
Quantity II:
Let honey = 7x, water = 2x
New honey = 7x + 21, new water = 2x + 24
Initial difference = 7x – 2x = 5x = 5 × 9 = 45 litres
So, Quantity-I < Quantity-II
More Quantity Inequality Questions
(3374 ÷ 125.13)1/3 + (362 ÷ 11) = ?2 – 27.79
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
102.89 of 3.08 = 59.98% of 499.94 + √?
11.992 + (6.01 × 5.98) + ? = 350.03
7.898 × ? + 139.89` ` `-:` 14.23 = 4004.04 – 353.89
` `
156.76 + 14.08² + ?³ = √625.12 * 26.87
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
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