Question
In the question, two quantities I and II are given. You
have to solve both the quantities to establish the correct relation between Quantity-I and Quantity-II and choose the correct option. Quantity I: A 200 litres chemical mixture contains 25% acid and the rest is water. How much water should be added so that the final acid to water ratio becomes 1:3? Quantity II: In a container, the ratio of honey to water is 7:2. If 21 litres of honey and 24 litres of water are added, the ratio becomes 2:1. Find the initial difference in litres between honey and water.Solution
ATQ,
Quantity I:
Acid = 25% of 200 = 50 litres
Water = 75% of 200 = 150 litres
Let added water = x litres 
50×3=1×(150+x)
150=150+x
X = 0
Water to be added = 0 litres
Quantity II:
Let honey = 7x, water = 2x
New honey = 7x + 21, new water = 2x + 24
Initial difference = 7x – 2x = 5x = 5 × 9 = 45 litres
So, Quantity-I < Quantity-II
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