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ATQ,
Quantity I:
Acid = 25% of 200 = 50 litres
Water = 75% of 200 = 150 litres
Let added water = x litres 
50×3=1×(150+x)
150=150+x
X = 0
Water to be added = 0 litres
Quantity II:
Let honey = 7x, water = 2x
New honey = 7x + 21, new water = 2x + 24
Initial difference = 7x – 2x = 5x = 5 × 9 = 45 litres
So, Quantity-I < Quantity-II
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