Question
In the question, two quantities I and II are given. You
have to solve both the quantities to establish the correct relation between Quantity-I and Quantity-II and choose the correct option. Quantity I: A 200 litres chemical mixture contains 25% acid and the rest is water. How much water should be added so that the final acid to water ratio becomes 1:3? Quantity II: In a container, the ratio of honey to water is 7:2. If 21 litres of honey and 24 litres of water are added, the ratio becomes 2:1. Find the initial difference in litres between honey and water.Solution
ATQ,
Quantity I:
Acid = 25% of 200 = 50 litres
Water = 75% of 200 = 150 litres
Let added water = x litres 
50×3=1×(150+x)
150=150+x
X = 0
Water to be added = 0 litres
Quantity II:
Let honey = 7x, water = 2x
New honey = 7x + 21, new water = 2x + 24
Initial difference = 7x – 2x = 5x = 5 × 9 = 45 litres
So, Quantity-I < Quantity-II
M/14 : O/12 : : U/6 : ?
Find the missing number by analysing the pattern followed by the numbers in each row.
Select the number from among the given options that can replace the question mark (?) in the following table.
What number should replace the question mark?Â
Select the combination of numbers that when placed sequentially in the blanks of the given series will complete the series.
3 _ 3 _ 5 3 3 5 _ 3 3...
Select the number that can replace the question mark (?) in the following series.Â
Find the missing number.
Select the number which can be placed in the column of question mark sign.
F : 216 : : I : ?
What number should come in the place of question mark?
Relevant for Exams:
