Question
A alone can complete the work in 36 days. B’s
efficiency is double that of A, and C’s efficiency is half of B’s efficiency. A and B start the work together, and after 6 days, C joins them. At that point, all three reduce their efficiency to 50% of their original efficiency. How many total days will it take to complete the work?Solution
A = 1/36 B = 36 * 1/2= 18 days C = 18 * 2/1 = 36 days A + B = 6/36 + 6/18 = 1/2 Remaining work = 1 – 1/2 = 1/2 They reduced the efficiency by 50%, then complete the whole work in = 1/72 + 1/36 + 1/72 = (1 + 2 + 1)/72 = 1/18 Half of the work completed with 50% of efficiency = 9 days Required time = 9 + 6 = 15 days
More Quantity Inequality Questions
What will be the value of expression if the signs ‘(+)’ and ‘(×)’ are interchanged?
63 + 7 ÷ 21 × 14 – 24 ÷ 6
...If all the alphabets of alphabetical series are numbered as 26-1 from A-Z then what is the sum of the numbers of letters of the word “ PARENT ”?
Which two signs should be interchanged in the following equation to make it correct:
640 ÷ 80 + 6 × 20 – 10 = 58
