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    Question

    Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer as,

    Quantity I: The ratio of the ages of A and B is 3:1, and

    the ratio of the ages of B to C is 3:5. If C’s age after 20 years equals A’s current age, and D’s age is 80% more than B’s age, what is the average age of A and D? Quantity II: A is 12 years older than B, and B is 10 years younger than C. The average age of A, B, C, and D is 30 years. If C’s age equals D’s age, find D’s age after 4 years.
    A Quantity I > Quantity II Correct Answer Incorrect Answer
    B Quantity I ≥ Quantity II Correct Answer Incorrect Answer
    C Quantity II > Quantity I Correct Answer Incorrect Answer
    D Quantity II ≥ Quantity I Correct Answer Incorrect Answer
    E Quantity I = Quantity II or Relation cannot be established Correct Answer Incorrect Answer

    Solution

    From quantity I, Ratio of the ages of A, B and C = 9:3:5 5x + 20 = 9x 4x = 20 x = 5 years D’s age = (3 * 5) * 180/100 = 27 years Average ages of A and D = (27 + 45)/2 = 36 years From quantity II, A – B = 12 C – B = 10 B = C – 10 A = 12 + C – 10 = C + 2 C = D A + B + C + D = 30 * 4 = 120 C + 2 + C – 10 + C + C = 120 4C = 128 C = 32 = D D + 4 = 36 Quantity I = Quantity II

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