Question
Quantity I: The speed of a boat in still water is 12
km/hr. It takes 4.5 hours to travel 24 km downstream and return. What is the speed of the stream? Quantity II: A boat takes 1.5 hours less to travel 36 km downstream than upstream. If the boat's speed in still water is 10 km/hr, find the speed of the stream.Solution
Solution: Quantity I: Let the speed of the stream = x km/hr. Downstream speed = (12 + x) km/hr, and upstream speed = (12 - x) km/hr. Time taken downstream = 24/(12 + x) Time taken upstream = 24/(12 - x) According to the question: 24/(12 + x) + 24/(12 - x) = 4.5 Solving for x: Cross-multiplying and simplifying, we get x = 4 km/hr. Quantity II: Let the speed of the stream = y km/hr. Downstream speed = 10 + y, and upstream speed = 10 - y. According to the question: 36/(10 - y) - 36/(10 + y) = 1.5 Solving for y: Cross-multiplying and simplifying, we get y = 2 km/hr. Answer: E (Quantity I > Quantity II)
If tan 3.5θ x tan 6.5θ = 1 then the value of tan 5θ is
If sin 23° = `12/13` , then tan 67° = ?
...
If cos4 p - sin4 p =
A tower is 60 meters high. From a point on the ground, the angle of elevation of the top of the tower is 30°. Find the distance of the point from the b...
Simplify the given equation:
Evaluate the following:
sin 60° × cos 30° + sin 30° × cos 60°
The Value of (sin38Ëš)/(cos52Ëš)+ (cos12Ëš)/(sin78Ëš)- 4cos²60Ëš is
What is the value of 1/(1+tan 2 θ ) + 1 / (1+cot 2 θ ) = ?
...Find the value of the given trigonometric expression:
(sin 22°cos 68° + cos²22°) × sin 30° + (cos 60°tan 45°) × sec 60°
...
Relevant for Exams:
