Question
Quantity-I: 'Asmita' is able to finish 32% of a task in
16 days. 'Ben' can complete the same task in 10 days fewer than 'Asmita'. Calculate the time it would take for both 'Asmita' and 'Ben' to complete 90% of the task together. Quantity-II: 18 days In the given problem, two quantities, I and II, are presented. You are required to solve both quantities and determine the correct relationship between them.Solution
ATQ, Quantity I: Time taken by ‘Asmita’ to complete the whole task = 16/0.32 = 50 days Time taken by ‘Ben’ to complete the whole task = 50 – 10 = 40 days Let the total task be = 200 units Efficiency of ‘Asmita’ = 200/50 = 4 units/day Efficiency of ‘Ben’ = 200/40 = 5 units/day Required time taken = 0.9 × 200/9 = 20 days Quantity II: 18 days
Which of the given trigonometric identities is incorrect ?
1. tan2 θ = sec2 θ - 1B. cosec2 θ = 1 + cot
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
? + 157.99 – 101.01 = 25.01 × 5.98
8.15 of 124.95 ÷ 40.13 + 249.84 X 14.18 - √325 X 149.87 = ? X 10.85
(1440.13 ÷ 31.77) × (√168.69 + 16) - (24.87% of 719.99) = ?
499.98% of (√440.8 + 12.922 ) - 12.02 of 4.82 = ? of 9.82 + 9.98% of 999.94
(363.89% of 224.98 – 319.86% of 134.94) ÷ ? = √(134.88 ÷ 15.25)
16.22 × 12.99 + 142.15 = ?
(98.999)2 - (9.9)2 - (14.9)2 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
