Question
Quantity 1: Q : A number, greater than one, the
difference between itself and its reciprocal is 40% of the sum of itself and its reciprocal. The square of the number is 'Q' (nearest to the integer) % less than its cube. Quantity 2: R : The income of Ram is 20% more than that of Gopal and the income of Suresh is 68% less, then the sum of the incomes of Ram & Gopal. Income of Suresh is 'R' % less than the income of Ram.Solution
For Quantity 1, Let the number be= x (x + 1/x) × 0.4 = x – 1/x 0.4x + 0.4/x = x – 1/x 0.6x = 1.4/x x2 = 1.4/0.6 = 7/3 x3 = (7/3)√(7/3) Q = [(7/3)√(7/3) – 7/3]/(7/3) × 100 = [√(7/3) – 1] × 100 = 52.75% For Quantity 2, Let the Income of Gopal be = 100 Rs., The Income of Ram will be = 1.2 × 100 = 120 Rs. Then, Income of Suresh = (100 + 120) × 0.32 = 220 × 0.32 = 70.4 R = (120 – 70.4)/120 × 100 = 41.33% = Q2 Therefore quantity 1 will be greater than quantity 2 Q1 > Q2
13 19 32 52 ? 113
1290, 1225, 1175, ?, 1112, 1095, 1085
? , 864, 432, 144, 36, 7.2
106, 124, 88, 142, ?, 160
What value should come in the place of (?) in the following number series?
5670, 1620, 540, 216, 108, ?
7, 9, 21, ?, 107, 197
71, 79, 88, 152, ?, 393
14, 20, 29, 44, 65, ?
What will come in place of the question mark (?) in the following series?
2.5, 6.5, 18.5, 54.5, 162.5, 486.5, ?
22, 37, 63, 98, 148, ?
