Question
A trader buys 500 shares of a company at ₹240 each. He
pays a 0.5% brokerage on the purchase. After two months, he sells all shares at ₹260 each, paying 0.5% brokerage on the sale. Find his net profit and percentage return on the total investment.Solution
ATQ,
Buying cost: Price per share = ₹240 Brokerage = 0.5% of 240 = 1.2 Total cost per share = 240 + 1.2 = 241.2 Total investment = 500 × 241.2 = ₹120,600 Selling proceeds: Selling price per share = ₹260 Brokerage = 0.5% of 260 = 1.3 Net sale price per share = 260 − 1.3 = 258.7 Total sale proceeds = 500 × 258.7 = ₹129,350 Profit: Profit = 129,350 − 120,600 = ₹8,750 Percentage return = (8750 / 120,600) × 100 = 7.25% Hence, Net Profit = ₹8,750 and Percentage Return = 7.25%
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
I. 2x2 – 5x – 12 = 0
II. 2y2 + 13y + 20 = 0
For 3x² − 10x − 8 = 0, find (1/α + 1/β).
I. x2 - 9x - 52 = 0
II. y2 - 16y + 63 = 0
I. 10x2 + 33x + 9 = 0
II. 2y2 + 13y + 21 = 0
I. 3x2 - 16x - 12 = 0
II. 2y2 + 11y + 9 = 0
I. 2y² - 11 y + 15 = 0
II. 2x² + 3x – 14 = 0
I). 5p2 - p - 4 = 0
II). q2 - 12q + 27 = 0
If the roots of the quadratic equation 5x² + 4x + 6 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
...I. y/16 = 4/y
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
