Question
If log₁₀(x² − 1) = log₁₀(4x − 3), find
x.Solution
ATQ,
x² − 1 = 4x − 3 → x² − 4x + 2 = 0 x = [4 ± √(16 − 8)]/2 = [4 ± √8]/2 = 2 ± √2 Domain: x > 1 ⇒ both valid.
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