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We are given the inequality: (x – 4)(6 – x) ≥ 0 Note that: (x – 4)(6 – x) = –(x – 4)(x – 6) So the inequality becomes: –(x – 4)(x – 6) ≥ 0 Multiply both sides by –1 (remember: inequality sign reverses): (x – 4)(x – 6) ≤ 0 We solve: (x – 4)(x – 6) ≤ 0 The critical points are: x = 4 and x = 6 Make a sign chart: · For x < 4: both factors negative → product positive · For 4 ≤ x ≤ 6: one factor negative, one positive → product negative or zero · For x > 6: both positive → product positive We want: (x – 4)(x – 6) ≤ 0 So, solution is: x ∈ [4, 6]
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