Question
Let a=i+j+k, b=2i+j−k, and c=a×b. The angle
between c and a is:Solution
Given the vectors: a=i+j+k b=2i+j–k c=a×b First, let's find the cross-product c=a×b: 
Since the dot product a ⋅ c =0, the vectors a and c are orthogonal (perpendicular). Therefore, the angle θ between c and a is π/2 or 90 degrees.
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