Question
Jason alone can complete a piece of work in 20 days. In how many days can Jamal alone do the same work, if both of them together can do the same work in 9 days?Ā
Solution
Letās assume the total work = 1 unit (or 1 whole work).
So, Jasonās 1 day work =Ā 1/20
Jason + Jamalās 1 day work together = 1/9
Jamalās 1 day work = (Jason + Jamal)'s 1 day work ā Jasonās 1 day work = 1/9 - 1/20 = 11/180
Jamal alone can complete the work inĀ 180/ 11 days, or approximately 16.36 days
More Quant Miscellaneous Questions
- In the expansion of (1 + x)¹ⵠ, what is the ratio of the coefficients of the 6th term to the 9th term?
- Marked price of an article is Rs. M, as it is marked by a certain price. Find the value of M. Statement I. If the shopkeeper gives a discount of 10%, so, t...
- A triangle has sides 7 cm, 24 cm, and 25 cm. Determine the largest angle in the triangle.
- If the homogeneous system of equations x + y + z = 0 2x + 3y + 4z = 0 has a non-trivial solution, then the value of k is: 3x + 5y + kz = 0
- A trader buys a stock at an average price of Rs. 240 per share. He sells one-third of his shares at a 10% profit and the remaining at a 20% profit. What is...
- 120Ā Ā 124Ā Ā 151Ā Ā 167Ā Ā Ā 292Ā Ā Ā ?
- 72, 81, 99, ?,Ā 162, 207
- Find the general solution of cos 3x = 1/2:
- Microsoft Windows, Google's Android, and Linux are all examples of what?
- A solid cylinder has a radius of 3 cm and a height of 10 cm. If it is melted and recast into a cone with a base radius of 3 cm, what will be the height of ...