Question
A person is standing 30 meters away from the base of a
building. If the angle of elevation from the person's eye level to the top of the building is 60 degrees, find the height of the building (assuming the person's eye level is 1.5 meters above the ground).Solution
Let the height of the building be h. The height from the eye level to the top is given by: tan 60 degrees = (h - 1.5)/30, where tan 60 degrees = √3 ≈ 1.732. Thus, h - 1.5 = 30 * 1.732 h - 1.5 = 51.96 h = 51.96 + 1.5 = 53.46 m. Correct Answer: c) 53.46 m
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Relevant for Exams:
