Question
In triangle ABC, if the sides are a = 13 cm, b = 14 cm,
and c = 15 cm, find the circumradius (R).Solution
Using the formula: R = (abc) / (4 × Area). Area using Heron’s formula: s = (13 + 14 + 15) / 2 = 21 cm, Area = √(21 × (21 - 13) × (21 - 14) × (21 - 15)) = √(21 × 8 × 7 × 6) = 84 cm². Thus, R = (13 × 14 × 15) / (4 × 84) = 8.125 cm.
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
...
Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is:
