Question
A man is standing 30 meters away from the foot of a
tree. The angle of elevation from his eyes to the top of the tree is 60 degrees. Find the height of the tree.Solution
Let the height of the tree be h meters. Using the tangent of the angle of elevation: tan(60°) = h / 30 √3 = h / 30 h = 30√3 meters Thus, the height of the tree is 30√3 meters.
In ∆ABC , G is the centroid , AB = 8 cm, BC= 12 cm and AC = 14 cm , find GD, where D is the mid-point of BC?
If angle between two sides of 4 cm & 5 cm of a triangle is 30°. what is the area of the triangle ?
If in a ΔABC, AD is internal angle bisector & D is a point on BC, AB = 8 cm, BC = 10 cm then what is BD:CD?
If O is circumcentre of acute angled triangle ABC, if ∠ OBC = 300 then ∠BAC = ?
The area of a field in the shape of a hexagon is 2400 √ 3 m2  ? What will be the cost of fencing it at ₹18.50 per metre?
If G is the centroid and AD, BE, CF are three medians of ∆ABC with area 42 cm 2 , then the area of ∆BGD is?
If O is circumcentre of acute angled triangle ABC, if ∠ OBC = 150 then ∠BAC = ?
If I is the incentre of ΔABC , if ∠BAC = 500 , then what is the measure of ∠BIC?
AB and AC are two Chords of a circle with centre O. M and N are the mid points of the chords respectively. The line OM and ON are extended which interse...