Question
A sum of ₹20,000 is invested at an annual rate of
interest of 10%. Calculate the difference between simple interest and compound interest after 3 years.Solution
Simple interest (SI) = P × R × T / 100 = 20,000 × 10 × 3 / 100 = ₹6,000. Compound interest (CI) = P(1 + R/100)^T - P = 20,000(1 + 10/100)^3 - 20,000 = 20,000(1.1)^3 - 20,000 = 26,620 - 20,000 = ₹6,620. Difference = ₹6,620 - ₹6,000 = ₹620.
I. 27x6 - 152x3 + 125 = 0
II. 216y6 - 91y3 + 8 = 0
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
- If the quadratic equation x² + 18x + n = 0 has real and equal roots, what is the value of n?
I. 5x + y = 37
II. 4y+ x = 15
I. 88x² - 13 x – 56 = 0
II. 15 y² + 41 y + 28 = 0
I. 77x² - 25x – 72 = 0
II. 42y² + 13y – 42 = 0
I. 6y2 – 23y + 20 = 0
II. 4x2 – 24 x + 35 = 0
I. 63x2 + 148x + 77 = 0
II. 21y2 + 89y + 88 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 40x² + 81x + 35 = 0
II. 63y² + 103y + 42 = 0