Question
The sides of a triangle are 13 cm, 14 cm, and 15 cm.
What is the radius of the circumcircle of this triangle?Solution
The area of the triangle can be calculated using Heron's formula. The semiperimeter s = (13 + 14 + 15) / 2 = 21 cm. The area A = √[21(21 - 13)(21 - 14)(21 - 15)] = √[21 × 8 × 7 × 6] = √7056 = 84 cm². The circumradius R is given by R = (abc) / (4A), where a = 13, b = 14, c = 15. So R = (13 × 14 × 15) / (4 × 84) = 2730 / 336 = 8.125 cm ≈ 8 cm. Correct answer: c) 8 cm
3 √2197.08 × 5.15 + 13.302 = √675.99 + ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1587.9 + 9650.98 + 10612.8 =?3 - 2536.67
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
2660.03 ÷ 69.98 x 49.9 = ? + 10.32
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Which of the given trigonometric identities is incorrect ?
1. tan2 θ = sec2 θ - 1B. cosec2 θ = 1 + cot
80.08% of 1250.25 + 64.02% of 1200 = 24.02 × 36.025 + ?% of 2259.98
?% of 309.99 = 40.01% of 249.99 + 295.98% of 49.99
Relevant for Exams:
